Date | May 2009 | Marks available | 3 | Reference code | 09M.1.sl.TZ2.1 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Find | Question number | 1 | Adapted from | N/A |
Question
A rectangle is 2680 cm long and 1970 cm wide.
Find the perimeter of the rectangle, giving your answer in the form \(a \times {10^k}\), where \(1 \leqslant a \leqslant 10\) and \(k \in \mathbb{Z}\).
Find the area of the rectangle, giving your answer correct to the nearest thousand square centimetres.
Markscheme
Note: Unit penalty (UP) applies in this part
(2680 + 1970) × 2 (M1)
(UP) = 9.30 × 103 cm (A1)(A1) (C3)
Notes: Award (M1) for correct formula.
(A1) for 9.30 (Accept 9.3).
(A1) for 103.
[3 marks]
2680 × 1970 (M1)
= 5279600 (A1)
= 5,280,000 (5280 thousand) (A1)(ft) (C3)
Note: Award (M1) for correctly substituted formula.
Accept 5.280 × 106.
Note: The last (A1) is for specified accuracy, (ft) from their answer.
The (AP) for the paper is not applied here.
[3 marks]
Examiners report
This question was well answered by many candidates although the majority lost a mark as a unit penalty in part (a). Some candidates used the wrong formula for the perimeter. Most could give their answer in standard form.
This question was well answered by many candidates although the majority lost a mark as a unit penalty in part (a). Some candidates used the wrong formula for the perimeter. Most could give their answer in standard form.