Calculate exactly \(\frac{{{{(3 \times 2.1)}^3}}}{{7 \times 1.2}}\).

Write the answer to part (a) correct to 2 significant figures.

Calculate the percentage error when the answer to part (a) is written correct to 2 significant figures.

Write your answer to part (c) in the form \(a \times {10^k}\) where \(1 \leqslant a < 10{\text{ and }}k \in \mathbb{Z}\).

\(29.7675\)     (A1)     (C1)

Note: Accept exact answer only.

[1 mark]

\(30\)     (A1)(ft)     (C1)

[1 mark]

\(\frac{{30 - 29.7675}}{{29.7675}} \times 100\% \)     (M1)

For correct formula with correct substitution.

\( = 0.781\% \)     accept \(0.78\% \) only if formula seen with \(29.7675\) as denominator     (A1)(ft)     (C2)

[2 marks]

\(7.81 \times {10^{ - 1}}\% \) (\(7.81 \times {10^{ - 3}}\) with no percentage sign)     (A1)(ft)(A1)(ft)     (C2)

[2 marks]

Many candidates gained maximum marks. The common errors were in the initial calculation due to forgetting to use brackets when entering the denominator into the GDC; using 2 decimal places instead of 2 significant figures in part (b); and using the wrong value as the denominator in part (c). Some candidates were still using the old Information booklet with the wrong formula for percentage error. Because examiners believed that the wording was ambiguous the correct answer given to 2 significant figures was awarded full marks for this part.

Many candidates gained maximum marks. The common errors were in the initial calculation due to forgetting to use brackets when entering the denominator into the GDC; using 2 decimal places instead of 2 significant figures in part (b); and using the wrong value as the denominator in part (c). Some candidates were still using the old Information booklet with the wrong formula for percentage error. Because examiners believed that the wording was ambiguous the correct answer given to 2 significant figures was awarded full marks for this part.

Many candidates gained maximum marks. The common errors were in the initial calculation due to forgetting to use brackets when entering the denominator into the GDC; using 2 decimal places instead of 2 significant figures in part (b); and using the wrong value as the denominator in part (c). Some candidates were still using the old Information booklet with the wrong formula for percentage error. Because examiners believed that the wording was ambiguous the correct answer given to 2 significant figures was awarded full marks for this part.

Many candidates gained maximum marks. The common errors were in the initial calculation due to forgetting to use brackets when entering the denominator into the GDC; using 2 decimal places instead of 2 significant figures in part (b); and using the wrong value as the denominator in part (c). Some candidates were still using the old Information booklet with the wrong formula for percentage error. Because examiners believed that the wording was ambiguous the correct answer given to 2 significant figures was awarded full marks for this part.