| Date | November 2008 | Marks available | 1 | Reference code | 08N.1.sl.TZ0.1 |
| Level | SL only | Paper | 1 | Time zone | TZ0 |
| Command term | Write down | Question number | 1 | Adapted from | N/A |
Question
Given that \(h = \sqrt {{\ell ^2} - \frac{{{d^2}}}{4}} \) ,
Calculate the exact value of \(h\) when \(\ell = 0.03625\) and \(d = 0.05\) .
Write down the answer to part (a) correct to three decimal places.
Write down the answer to part (a) correct to three significant figures.
Write down the answer to part (a) in the form \(a \times {10^k}\) , where \(1 \leqslant a < 10{\text{, }}k \in \mathbb{Z}\).
Markscheme
\(h = \sqrt {{{0.03625}^2} - \frac{{{{0.05}^2}}}{4}} \) (M1)
\( = 0.02625\) (A1) (C2)
Note: Award (A1) only for \(0.0263\) seen without working
[2 marks]
\(0.026\) (A1)(ft) (C1)
[1 mark]
\(0.0263\) (A1)(ft) (C1)
[1 mark]
\(2.625 \times {10^{ - 2}}\)
for \(2.625\) (ft) from unrounded (a) only (A1)(ft)
for \( \times {10^{ - 2}}\) (A1)(ft) (C2)
[2 marks]
Examiners report
This was answered correctly by the majority of the candidates however some candidates entered the numbers incorrectly and arrived at the wrong answer.
Correction to decimal places was less well attempted than to significant figures.
Correction to decimal places was less well attempted than to significant figures.
Most made a successful attempt to change their answer to part (a) into scientific notation. Some were penalised for not using their answer to (a).
