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Date May 2013 Marks available 2 Reference code 13M.1.hl.TZ1.1
Level HL only Paper 1 Time zone TZ1
Command term Find Question number 1 Adapted from N/A

Question

If w = 2 + 2i , find the modulus and argument of w.

[2]
a.

Given \(z = \cos \left( {\frac{{5\pi }}{6}} \right) + {\text{i}}\sin \left( {\frac{{5\pi }}{6}} \right)\), find in its simplest form \({w^4}{z^6}\).

[4]
b.

Markscheme

modulus \( = \sqrt 8 \)     A1

argument \( = \frac{\pi }{4}\) (accept 45°)     A1

Note: A0 if extra values given.

 

[2 marks]

a.

METHOD 1

\({w^4}{z^6} - 64{e^{\pi {\text{i}}}} \times {e^{5\pi {\text{i}}}}\)     (A1)(A1) 

Note: Allow alternative notation.

 

\( = 64{e^{6\pi {\text{i}}}}\)     (M1)

\( = 64\)     A1

 

METHOD 2

\({w^4} = - 64\)     (M1)(A1)

\({z^6} = - 1\)     (A1)

\({w^4}{z^6} = 64\)     A1

[4 marks]

b.

Examiners report

Those who tackled this question were generally very successful. A few, with varying success, tried to work out the powers of the complex numbers by multiplying the Cartesian form rather than using de Moivre’s Theorem.

a.

Those who tackled this question were generally very successful. A few, with varying success, tried to work out the powers of the complex numbers by multiplying the Cartesian form rather than using de Moivre’s Theorem.

b.

Syllabus sections

Topic 1 - Core: Algebra » 1.5 » Complex numbers: the number \({\text{i}} = \sqrt { - 1} \) ; the terms real part, imaginary part, conjugate, modulus and argument.
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