Date | May 2008 | Marks available | 7 | Reference code | 08M.2.hl.TZ1.10 |
Level | HL only | Paper | 2 | Time zone | TZ1 |
Command term | Find | Question number | 10 | Adapted from | N/A |
Question
Find, in its simplest form, the argument of \({\left( {\sin \theta + {\text{i}}(1 - \cos \theta )} \right)^2}\) where \(\theta \) is an acute angle.
Markscheme
\({\left( {\sin \theta + {\text{i}}(1 - \cos \theta )} \right)^2} = {\sin ^2}\theta - {(1 - \cos \theta )^2} + {\text{i}}2\sin \theta (1 - \cos \theta )\) M1A1
Let \(\alpha \) be the required argument.
\(\tan \alpha = \frac{{2\sin \theta (1 - \cos \theta )}}{{{{\sin }^2}\theta - {{(1 - \cos \theta )}^2}}}\) M1
\( = \frac{{2\sin \theta (1 - \cos \theta )}}{{(1 - {{\cos }^2}\theta ) - (1 - 2\cos \theta + {{\cos }^2}\theta )}}\) (M1)
\( = \frac{{2\sin \theta (1 - \cos \theta )}}{{2\cos \theta (1 - \cos \theta )}}\) A1
\( = \tan \theta \) A1
\(\alpha = \theta \) A1
[7 marks]
Examiners report
Very few candidates scored more than the first two marks in this question. Some candidates had difficulty manipulating trigonometric identities. Most candidates did not get as far as defining the argument of the complex expression.