Date | May 2009 | Marks available | 6 | Reference code | 09M.1.hl.TZ1.1 |
Level | HL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 1 | Adapted from | N/A |
Question
Consider the complex numbers z=1+2iz=1+2i and w=2+aiw=2+ai , where a∈R .
Find a when
(a) |w|=2|z|; ;
(b) Re(zw)=2Im(zw) .
Markscheme
(a) |z|=√5 and |w|=√4+a2
|w|=2|z|
√4+a2=2√5
attempt to solve equation M1
Note: Award M0 if modulus is not used.
a=±4 A1A1 N0
(b) zw=(2−2a)+(4+a)i A1
forming equation 2−2a=2(4+a) M1
a=−32 A1 N0
[6 marks]
Examiners report
Most candidates made good attempts to answer this question. Weaker candidates did not get full marks due to difficulties recognizing the notation and working with modulus of a complex number.
Syllabus sections
Topic 1 - Core: Algebra » 1.5 » Complex numbers: the number i=√−1 ; the terms real part, imaginary part, conjugate, modulus and argument.
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