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Date May 2009 Marks available 6 Reference code 09M.1.hl.TZ1.1
Level HL only Paper 1 Time zone TZ1
Command term Find Question number 1 Adapted from N/A

Question

Consider the complex numbers z=1+2iz=1+2i and w=2+aiw=2+ai , where aR .

Find a when

(a)     |w|=2|z|; ;

(b)     Re(zw)=2Im(zw) .

Markscheme

(a)     |z|=5 and |w|=4+a2

|w|=2|z|

4+a2=25

attempt to solve equation     M1

Note: Award M0 if modulus is not used.

 

a=±4     A1A1     N0

 

(b)     zw=(22a)+(4+a)i     A1

forming equation 22a=2(4+a)     M1

a=32     A1     N0

[6 marks]

Examiners report

Most candidates made good attempts to answer this question. Weaker candidates did not get full marks due to difficulties recognizing the notation and working with modulus of a complex number.

Syllabus sections

Topic 1 - Core: Algebra » 1.5 » Complex numbers: the number i=1 ; the terms real part, imaginary part, conjugate, modulus and argument.
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