User interface language: English | Español

Date May 2018 Marks available 1 Reference code 18M.1.sl.TZ2.4
Level SL Paper 1 Time zone TZ2
Command term Derive Question number 4 Adapted from N/A

Question

What is the percentage yield when 2.0 g of ethene, C2H4, is formed from 5.0 g of ethanol, C2H5OH?
Mr(ethene) = 28; Mr(ethanol) = 46

A.     \(\frac{{2.0}}{{28}} \times \frac{{5.0}}{{46}} \times 100\)

B.     \(\frac{{\frac{{2.0}}{{28}}}}{{\frac{{5.0}}{{46}}}} \times 100\)

C.     \(\frac{{28}}{{2.0}} \times \frac{{5.0}}{{46}} \times 100\)

D.     \(\frac{{\frac{{28}}{{2.0}}}}{{\frac{{5.0}}{{46}}}} \times 100\)

Markscheme

B

Examiners report

[N/A]

Syllabus sections

Core » Topic 1: Stoichiometric relationships » 1.3 Reacting masses and volumes
Show 166 related questions

View options