What is the pressure, in Pa, if 3 mol of gas occupies ${\text{500 c}}{{\text{m}}^{\text{3}}}$ at 25 °C?

Given:     $R = 8.31{\text{ J}}\,{{\text{K}}^{ - 1}}{\text{mo}}{{\text{l}}^{ - 1}}$

     ${10^{ - 3{\text{ }}}}{{\text{m}}^3} = {10^3}{\text{ c}}{{\text{m}}^3}$

A.     $\frac{{3 \times 8.31 \times 298}}{{500}}$

B.     $\frac{{3 \times 8.31 \times 25}}{{0.0005}}$

C.     $\frac{{3 \times 8.31 \times 25}}{{500}}$

D.     $\frac{{3 \times 8.31 \times 298}}{{0.0005}}$

D