The volume occupied by one mole of an ideal gas at 273 K and \(1.01 \times {10^5}{\text{ Pa}}\) is \({\text{22.4 d}}{{\text{m}}^{\text{3}}}\). What volume, in \({\text{d}}{{\text{m}}^{\text{3}}}\), is occupied by 3.20 g \({{\text{O}}_{\text{2}}}{\text{(g)}}\) at 273 K and \(1.01 \times {10^5}{\text{ Pa}}\)?

A.     2.24

B.     4.48

C.     22.4

D.     71.7

A

One respondent stated that he/she was not sure if memorization of standard pressure in Pa was required for this question. In this question candidates had first to calculate the amount occupied by 3.20 g of \({{\text{O}}_{\text{2}}}{\text{(g)}}\). This was found by dividing 3.20 by \(32.00 = 0.100{\text{ mol}}\). Then, the volume in \({\text{d}}{{\text{m}}^{\text{3}}}\) was obtained by simply multiplying 0.100 by 22.4, giving an answer of \({\text{2.24 d}}{{\text{m}}^{\text{3}}}\), meaning A is the correct answer. The conditions of temperature and pressure were the same at 273 K and \({\text{1.01}} \times {\text{1}}{{\text{0}}^{\text{5}}}{\text{ Pa}}\). 49.15% of candidates got the correct answer.