4.0 g of solid sodium hydroxide is added to ${\text{0.10 d}}{{\text{m}}^{\text{3}}}$ of ${\text{1.0 mol d}}{{\text{m}}^{ - 3}}$ aqueous sulfuric acid.
$${\text{2NaOH(s) + }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{(aq) }} \to {\text{ N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{(aq) + 2}}{{\text{H}}_{\text{2}}}{\text{O(l)}}$$
Which statement is correct?

A.     Neither reactant is in excess.

B.     0.10 mol ${\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$ is formed.

C.     Excess ${{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$ remains in solution.

D.     Excess NaOH remains in solution.

C