Date | May 2013 | Marks available | 7 | Reference code | 13M.1.sl.TZ2.6 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
A rocket moving in a straight line has velocity \(v\) km s–1 and displacement \(s\) km at time \(t\) seconds. The velocity \(v\) is given by \(v(t) = 6{{\rm{e}}^{2t}} + t\) . When \(t = 0\) , \(s = 10\) .
Find an expression for the displacement of the rocket in terms of \(t\) .
Markscheme
evidence of anti-differentiation (M1)
eg \(\int {(6{{\rm{e}}^{2t}} + t)} \)
\(s = 3{{\rm{e}}^{2t}} + \frac{{{t^2}}}{2} + C\) A2A1
Note: Award A2 for \(3{{\rm{e}}^{2t}}\) , A1 for \(\frac{{{t^2}}}{2}\) .
attempt to substitute (\(0\), \(10\)) into their integrated expression (even if \(C\) is missing) (M1)
correct working (A1)
eg \(10 = 3 + C\) , \(C = 7\)
\(s = 3{{\rm{e}}^{2t}} + \frac{{{t^2}}}{2} + 7\) A1 N6
Note: Exception to the FT rule. If working shown, allow full FT on incorrect integration which must involve a power of \({\rm{e}}\).
[7 marks]