Date | May 2013 | Marks available | 7 | Reference code | 13M.1.sl.TZ2.6 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
A rocket moving in a straight line has velocity v km s–1 and displacement s km at time t seconds. The velocity v is given by v(t)=6e2t+t . When t=0 , s=10 .
Find an expression for the displacement of the rocket in terms of t .
Markscheme
evidence of anti-differentiation (M1)
eg ∫(6e2t+t)
s=3e2t+t22+C A2A1
Note: Award A2 for 3e2t , A1 for t22 .
attempt to substitute (0, 10) into their integrated expression (even if C is missing) (M1)
correct working (A1)
eg 10=3+C , C=7
s=3e2t+t22+7 A1 N6
Note: Exception to the FT rule. If working shown, allow full FT on incorrect integration which must involve a power of e.
[7 marks]