Date | November 2015 | Marks available | 3 | Reference code | 15N.2.sl.TZ0.6 |
Level | SL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
The velocity v ms−1 of a particle after t seconds is given by
v(t)=(0.3t+0.1)t−4, for 0≤t≤5
The following diagram shows the graph of v.
Find the value of t when the particle is at rest.
[3]
a.
Find the value of t when the acceleration of the particle is 0.
[3]
b.
Markscheme
recognizing particle at rest when v=0 (M1)
eg(0.3t+0.1)t−4=0, x-intercept on graph of v
t=4.27631
t=4.28 (seconds) A2 N3
[3 marks]
a.
valid approach to find t when a is 0 (M1)
egv′(t)=0, v minimum
t=1.19236
t=1.19 (seconds) A2 N3
[3 marks]
Total [6 marks]
b.
Examiners report
[N/A]
a.
[N/A]
b.
Syllabus sections
Topic 6 - Calculus » 6.6 » Kinematic problems involving displacement s, velocity v and acceleration a.
Show 53 related questions