User interface language: English | Español

Date May 2019 Marks available 2 Reference code 19M.2.SL.TZ2.S_2
Level Standard Level Paper Paper 2 Time zone Time zone 2
Command term Find Question number S_2 Adapted from N/A

Question

Let f ( x ) = 4 2 e x . The following diagram shows part of the graph of f .

Find the x -intercept of the graph of f .

[2]
a.

The region enclosed by the graph of f , the x -axis and the y -axis is rotated 360º about the x -axis. Find the volume of the solid formed.

[3]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

valid approach          (M1)

eg    f ( x ) = 0 ,    4 2 e x = 0

0.693147

x = ln 2 (exact), 0.693      A1 N2

[2 marks]

a.

attempt to substitute either their correct limits or the function into formula         (M1)

involving  f 2

eg    0 0.693 f 2 ,    π ( 4 2 e x ) 2 d x ,    0 ln 2 ( 4 2 e x ) 2

3.42545

volume = 3.43     A2 N3

[3 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 5 —Calculus » SL 5.5—Integration introduction, areas between curve and x axis
Show 162 related questions
Topic 5 —Calculus » SL 5.11—Definite integrals, areas under curve onto x-axis and areas between curves
Topic 5 —Calculus

View options