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Date May 2019 Marks available 2 Reference code 19M.1.SL.TZ1.S_7
Level Standard Level Paper Paper 1 (without calculator) Time zone Time zone 1
Command term Find Question number S_7 Adapted from N/A

Question

A particle P starts from point O and moves along a straight line. The graph of its velocity, v  ms−1 after t seconds, for 0 ≤ t ≤ 6 , is shown in the following diagram.

The graph of v has t -intercepts when t = 0, 2 and 4.

The function s ( t ) represents the displacement of P from O after t seconds.

It is known that P travels a distance of 15 metres in the first 2 seconds. It is also known that  s ( 2 ) = s ( 5 ) and  2 4 v d t = 9 .

Find the value of  s ( 4 ) s ( 2 ) .

[2]
a.

Find the total distance travelled in the first 5 seconds.

[5]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

recognizing relationship between v and s      (M1)

eg      v = s ,   s = v

s ( 4 ) s ( 2 ) = 9       A1  N2

[2 marks]

a.

correctly interpreting distance travelled in first 2 seconds (seen anywhere, including part (a) or the area of 15 indicated on diagram)        (A1)

eg     0 2 v = 15 s ( 2 ) = 15

valid approach to find total distance travelled       (M1)

eg    sum of 3 areas,   0 4 v + 4 5 v ,  shaded areas in diagram between 0 and 5

Note: Award M0 if only  0 5 | v | is seen.

correct working towards finding distance travelled between 2 and 5 (seen anywhere including within total area expression or on diagram)       (A1)

eg    2 4 v 4 5 v ,   2 4 v = 4 5 | v | ,   4 5 v d t = 9 ,   s ( 4 ) s ( 2 ) [ s ( 5 ) s ( 4 ) ] ,

equal areas 

correct working using s ( 5 ) = s ( 2 )       (A1)

eg    15 + 9 ( 9 ) ,   15 + 2 [ s ( 4 ) s ( 2 ) ] ,   15 + 2 ( 9 ) ,   2 × s ( 4 ) s ( 2 ) ,   48 15

total distance travelled = 33 (m)        A1   N2

[5 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 5 —Calculus » SL 5.5—Integration introduction, areas between curve and x axis
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