Find the gradient of $L$.

Find the equation of $L$ in the form $y = mx + c$.

Find the $x$-coordinate of point A.

$- 3$     (A1)(A1)     (C2)

Notes:     Award (A1) for 3 and (A1) for a negative value.

Award (A1)(A0) for either $3x$ or $- 3x$.

[2 marks]

$6 =  - 3(2) + c$$\,\,\,$OR$\,\,\,$$(y - 6) =  - 3(x - 2)$     (M1)

Note:     Award (M1) for substitution of their gradient from part (a) into a correct equation with the coordinates $(2,{\text{ }}6)$ correctly substituted.

$y =  - 3x + 12$     (A1)(ft)     (C2)

Notes:     Award (A1)(ft) for their correct equation. Follow through from part (a).

If no method seen, award (A1)(A0) for $y =  - 3x$.

Award (A1)(A0) for $- 3x + 12$.

[2 marks]

$0 =  - 3x + 12$     (M1)

Note:     Award (M1) for substitution of $y = 0$ in their equation from part (b).

$(x = ){\text{ }}4$     (A1)(ft)     (C2)

Notes:     Follow through from their equation from part (b). Do not follow through if no method seen. Do not award the final (A1) if the value of $x$ is negative or zero.

[2 marks]