Write down

(i)     the gradient of ${L_1}$;

(ii)     the $y$-intercept of ${L_1}$.

The line ${L_2}$ is parallel to ${L_1}$ and passes through the point ${\text{P}}(0,{\text{ }}3)$.

Write down the equation of ${L_2}$.

The line ${L_2}$ is parallel to ${L_1}$ and passes through the point ${\text{P}}(0,{\text{ }}3)$.

Find the $x$-coordinate of the point where ${L_2}$ crosses the $x$-axis.

(i)     $- 2$     (A1)     (C1)

(ii)     $10$     (A1)     (C1)

$2x + y - 3 = 0$     (A1)(ft)(A1)     (C2)

Notes: Award (A1)(ft) for gradient, (A1) for correct $y$-intercept.

The answer must be an equation.

$- 2x + 3 = 0\;\;\;$or equivalent     (M1)

$(x = ){\text{ }}1.5$     (A1)(ft)     (C2)

Notes: Follow through from their equation in part (b). If answer given as coordinates $(1.5,{\text{ }}0)$ award at most (M1)(A0) if working seen or (A1)(A0) if no working seen.