Date | May 2010 | Marks available | 3 | Reference code | 10M.1.sl.TZ2.4 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Find | Question number | 4 | Adapted from | N/A |
Question
The straight line, L1, has equation \(y = - \frac{1}{2}x - 2\).
Write down the y intercept of L1.
Write down the gradient of L1.
The line L2 is perpendicular to L1 and passes through the point (3, 7).
Write down the gradient of the line L2.
The line L2 is perpendicular to L1 and passes through the point (3, 7).
Find the equation of L2. Give your answer in the form ax + by + d = 0 where \(a,{\text{ }}b,{\text{ }}d \in \mathbb{Z}\).
Markscheme
–2 (A1) (C1)
Note: Accept (0, –2).
[1 mark]
\( - \frac{1}{2}\) (A1) (C1)
[1 mark]
2 (A1)(ft) (C1)
Note: Follow through from their answer to part (b).
[1 mark]
y = 2x + c (can be implied)
7 = 2 × 3 + c (M1)
c = 1 (A1)(ft)
y = 2x + 1
Notes: Award (M1) for substitution of (3, 7), (A1)(ft) for c.
Follow through from their answer to part (c).
OR
y – 7 = 2(x – 3) (M1)(M1)
Note: Award (M1) for substitution of their answer to part (c), (M1) for substitution of (3, 7).
2x – y + 1 = 0 or –2x + y – 1 = 0 (A1)(ft) (C3)
Note: Award (A1)(ft) for their equation in the stated form.
[3 marks]
Examiners report
Although the first three parts of this question were well answered, with most candidates knowing how to find the y intercept, gradient of a given line and gradient of the perpendicular line, very few candidates could find the equation of the perpendicular line and correctly state it in the required form.
Although the first three parts of this question were well answered, with most candidates knowing how to find the y intercept, gradient of a given line and gradient of the perpendicular line, very few candidates could find the equation of the perpendicular line and correctly state it in the required form.
Although the first three parts of this question were well answered, with most candidates knowing how to find the y intercept, gradient of a given line and gradient of the perpendicular line, very few candidates could find the equation of the perpendicular line and correctly state it in the required form.
Although the first three parts of this question were well answered, with most candidates knowing how to find the y intercept, gradient of a given line and gradient of the perpendicular line, very few candidates could find the equation of the perpendicular line and correctly state it in the required form.