Find the coordinates of P and of Q.

A second line with equation x − y = 3 intersects the line PQ at the point A. Find the coordinates of A.

$0 + 2y = 12$ or $x + 2(0) = 12$     (M1)

P(0, 6)     (accept $x = 0$, $y = 6$)     (A1)

Q(12, 0)     (accept $x = 12$, $y = 0$)     (A1)     (C3)

Notes: Award (M1) for setting either value to zero.

Missing coordinate brackets receive (A0) the first time this occurs.

Award (A0)(A1)(ft) for P(0, 12) and Q(6, 0).

[3 marks]

$x + 2(x - 3) = 12$     (M1)

(6, 3)     (accept $x = 6$, $y = 3$)     (A1)(A1)     (C3)

Note: (A1) for each correct coordinate.

Missing coordinate brackets receive (A0)(A1) if this is the first time it occurs.

[3 marks]

Most candidates could find the x and y intercepts but many wrote the coordinates the wrong way around. A number of candidates did not label their coordinates as P and Q or did not include parentheses.

In this part many had trouble recognising the need to solve the two simultaneous equations.