Date | May 2016 | Marks available | 1 | Reference code | 16M.1.sl.TZ2.12 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Write down | Question number | 12 | Adapted from | N/A |
Question
The equation of the straight line \({L_1}\) is \(y = 2x - 3.\)
Write down the \(y\)-intercept of \({L_1}\) .
Write down the gradient of \({L_1}\) .
The line \({L_2}\) is parallel to \({L_1}\) and passes through the point \((0,\,\,3)\) .
Write down the equation of \({L_2}\) .
The line \({L_3}\) is perpendicular to \({L_1}\) and passes through the point \(( - 2,\,\,6).\)
Write down the gradient of \({L_3}.\)
Find the equation of \({L_3}\) . Give your answer in the form \(ax + by + d = 0\) , where \(a\) , \(b\) and \(d\) are integers.
Markscheme
\((0,\,\, - 3)\) (A1) (C1)
Note: Accept \( - 3\) or \(y = - 3.\)
\(2\) (A1) (C1)
\(y = 2x + 3\) (A1)(ft) (C1)
Note: Award (A1)(ft) for correct equation. Follow through from part (b)
Award (A0) for \({L_2} = 2x + 3\).
\( - \frac{1}{2}\) (A1)(ft) (C1)
Note: Follow through from part (b).
\(6 = - \frac{1}{2}( - 2) + c\) (M1)
\(c = 5\) (may be implied)
OR
\(y - 6 = - \frac{1}{2}(x + 2)\) (M1)
Note: Award (M1) for correct substitution of their gradient in part (d) and the point \(( - 2,\,\,6)\). Follow through from part (d).
\(x + 2y - 10 = 0\) (or any integer multiple) (A1)(ft) (C2)
Note: Follow through from (d). The answer must be in the form \(ax + by + d = 0\) for the (A1)(ft) to be awarded. Accept any integer multiple.
Examiners report
Question 12: Linear function.
Many candidates demonstrated a good understanding of linear functions so successfully found the \(y\)-intercepts, gradient and equation in the form \(y = mx + c\). However only the very best were able to rewrite this in the form \(ax + by + d = 0\) where \(a\), \(b\) and \(d\) are integers.
Question 12: Linear function.
Many candidates demonstrated a good understanding of linear functions so successfully found the \(y\)-intercepts, gradient and equation in the form \(y = mx + c\). However only the very best were able to rewrite this in the form \(ax + by + d = 0\) where \(a\), \(b\) and \(d\) are integers.
Question 12: Linear function.
Many candidates demonstrated a good understanding of linear functions so successfully found the \(y\)-intercepts, gradient and equation in the form \(y = mx + c\). However only the very best were able to rewrite this in the form \(ax + by + d = 0\) where \(a\), \(b\) and \(d\) are integers.
Question 12: Linear function.
Many candidates demonstrated a good understanding of linear functions so successfully found the \(y\)-intercepts, gradient and equation in the form \(y = mx + c\). However only the very best were able to rewrite this in the form \(ax + by + d = 0\) where \(a\), \(b\) and \(d\) are integers.
Question 12: Linear function.
Many candidates demonstrated a good understanding of linear functions so successfully found the \(y\)-intercepts, gradient and equation in the form \(y = mx + c\). However only the very best were able to rewrite this in the form \(ax + by + d = 0\) where \(a\), \(b\) and \(d\) are integers.