| Date | May 2017 | Marks available | 2 | Reference code | 17M.1.sl.TZ1.2 |
| Level | SL only | Paper | 1 | Time zone | TZ1 |
| Command term | Calculate | Question number | 2 | Adapted from | N/A |
Question
In the Canadian city of Ottawa:
\[\begin{array}{*{20}{l}} {{\text{97% of the population speak English,}}} \\ {{\text{38% of the population speak French,}}} \\ {{\text{36% of the population speak both English and French.}}} \end{array}\]
The total population of Ottawa is \(985\,000\).
Calculate the percentage of the population of Ottawa that speak English but not French.
Calculate the number of people in Ottawa that speak both English and French.
Write down your answer to part (b) in the form \(a \times {10^k}\) where \(1 \leqslant a < 10\) and k \( \in \mathbb{Z}\).
Markscheme
\(97 - 36\) (M1)
Note: Award (M1) for subtracting 36 from 97.
OR
(M1)
Note: Award (M1) for 61 and 36 seen in the correct places in the Venn diagram.
\( = 61{\text{ }}(\% )\) (A1) (C2)
Note: Accept 61.0 (%).
[2 marks]
\(\frac{{36}}{{100}} \times 985\,000\) (M1)
Note: Award (M1) for multiplying 0.36 (or equivalent) by \(985\,000\).
\( = 355\,000{\text{ }}(354\,600)\) (A1) (C2)
[2 marks]
\(3.55 \times {10^5}{\text{ }}(3.546 \times {10^5})\) (A1)(ft)(A1)(ft) (C2)
Note: Award (A1)(ft) for 3.55 (3.546) must match part (b), and (A1)(ft) \( \times {10^5}\).
Award (A0)(A0) for answers of the type: \(35.5 \times {10^4}\). Follow through from part (b).
[2 marks]
