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Date May 2012 Marks available 2 Reference code 12M.2.sl.TZ1.4
Level SL only Paper 2 Time zone TZ1
Command term Find Question number 4 Adapted from N/A

Question

The graph of y=(x1)sinx , for 0x5π2 , is shown below.


The graph has x-intercepts at 0, 1, π and k .

Find k .

[2]
a.

The shaded region is rotated 360 about the x-axis. Let V be the volume of the solid formed.

Write down an expression for V .

[3]
b.

The shaded region is rotated 360 about the x-axis. Let V be the volume of the solid formed.

Find V .

[2]
c.

Markscheme

evidence of valid approach     (M1)

e.g. y=0 , sinx=0

2π=6.283185

k=6.28     A1     N2

[2 marks]

a.

attempt to substitute either limits or the function into formula     (M1)

(accept absence of dx )

e.g. V=πkπ(f(x))2dx , π((x1)sinx)2 , π6.28πy2dx

correct expression     A2     N3

e.g. π6.28π(x1)2sin2xdx , π2ππ((x1)sinx)2dx 

[3 marks]

b.

V=69.60192562

V=69.6     A2     N2

[2 marks]

c.

Examiners report

Candidates showed marked improvement in writing fully correct expressions for a volume of revolution. Common errors of course included the omission of dx , using the given domain as the upper and lower bounds of integration, forgetting to square their function and/or the omission of π . There were still many who were unable to use their calculator successfully to find the required volume.

a.

Candidates showed marked improvement in writing fully correct expressions for a volume of revolution. Common errors of course included the omission of dx , using the given domain as the upper and lower bounds of integration, forgetting to square their function and/or the omission of π . There were still many who were unable to use their calculator successfully to find the required volume.

b.

Candidates showed marked improvement in writing fully correct expressions for a volume of revolution. Common errors of course included the omission of  dx, using the given domain as the upper and lower bounds of integration, forgetting to square their function and/or the omission of π . There were still many who were unable to use their calculator successfully to find the required volume.

c.

Syllabus sections

Topic 2 - Functions and equations » 2.2 » The graph of a function; its equation y=f(x) .
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