Date | November 2012 | Marks available | 6 | Reference code | 12N.1.sl.TZ0.6 |
Level | SL only | Paper | 1 | Time zone | TZ0 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
The line L passes through the point (5,−4,10) and is parallel to the vector (4−25) .
Write down a vector equation for line L .
The line L intersects the x-axis at the point P. Find the x-coordinate of P.
Markscheme
any correct equation in the form {\boldsymbol{r}} = {\boldsymbol{a}} + t{\boldsymbol{b}} (accept any parameter for t)
where a is \left( {\begin{array}{*{20}{c}} 5\\ { - 4}\\ {10} \end{array}} \right) , and b is a scalar multiple of \left( {\begin{array}{*{20}{c}} 4\\ { - 2}\\ 5 \end{array}} \right) A2 N2
e.g. {\boldsymbol{r}} = \left( {\begin{array}{*{20}{c}} 5 \\ { - 4} \\ {10} \end{array}} \right) + t\left( {\begin{array}{*{20}{c}} 4 \\ { - 2} \\ 5 \end{array}} \right){\text{, }}{\boldsymbol{r}} = 5{\boldsymbol{i}} - 4{\boldsymbol{j}} + 10{\boldsymbol{k}} + t( - 8{\boldsymbol{i}} + 4{\boldsymbol{j}} - 10{\boldsymbol{k}})
Note: Award A1 for the form {\boldsymbol{a}} + t{\boldsymbol{b}} , A1 for L = {\boldsymbol{a}} + t{\boldsymbol{b}} , A0 for {\boldsymbol{r}} = {\boldsymbol{b}} + t{\boldsymbol{a}} .
[2 marks]
recognizing that y = 0 or z = 0 at x-intercept (seen anywhere) (R1)
attempt to set up equation for x-intercept (must suggest x \ne 0 ) (M1)
e.g. L = \left( {\begin{array}{*{20}{c}} x\\ 0\\ 0 \end{array}} \right) , 5 + 4t = x , r = \left( {\begin{array}{*{20}{c}} 1\\ 0\\ 0 \end{array}} \right)
one correct equation in one variable (A1)
e.g. - 4 - 2t = 0 , 10 + 5t = 0
finding t = - 2 A1
correct working (A1)
e.g. x = 5 + ( - 2)(4)
x = - 3 (accept ( - 3{\text{, }}0{\text{, }}0)) A1 N3
[6 marks]
Examiners report
In part (a), the majority of candidates correctly recognized the equation that contains the position and direction vectors of a line. However, we saw a large number of candidates who continue to write their equations using "L = ", rather than the mathematically correct "{\boldsymbol{r}} = " or "\left( {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right) = ". r and \left( {\begin{array}{*{20}{c}} x \\ y \\ z \end{array}} \right) represent vectors, whereas L is simply the name of the line. For part (b), very few candidates recognized that a general point on the x-axis will be given by the vector \left( {\begin{array}{*{20}{c}} x\\ 0\\ 0 \end{array}} \right) . Common errors included candidates setting their equation equal to\left( {\begin{array}{*{20}{c}} 0\\ 0\\ 0 \end{array}} \right) , or \left( {\begin{array}{*{20}{c}} 1\\ 0\\ 0 \end{array}} \right) , or even just the number 0.
In part (a), the majority of candidates correctly recognized the equation that contains the position and direction vectors of a line. However, we saw a large number of candidates who continue to write their equations using "L = ", rather than the mathematically correct "{\boldsymbol{r}} = " or "\left( {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right) = ". r and \left( {\begin{array}{*{20}{c}} x \\ y \\ z \end{array}} \right) represent vectors, whereas L is simply the name of the line. For part (b), very few candidates recognized that a general point on the x-axis will be given by the vector \left( {\begin{array}{*{20}{c}} x\\ 0\\ 0 \end{array}} \right) . Common errors included candidates setting their equation equal to\left( {\begin{array}{*{20}{c}} 0\\ 0\\ 0 \end{array}} \right) , or \left( {\begin{array}{*{20}{c}} 1\\ 0\\ 0 \end{array}} \right) , or even just the number 0.