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Date May Example question Marks available 2 Reference code EXM.1.AHL.TZ0.52
Level Additional Higher Level Paper Paper 1 Time zone Time zone 0
Command term Find Question number 52 Adapted from N/A

Question

Find the inverse of the matrix ( 1 2 1 1 1 2 2 1 4 ) .

[2]
a.

Hence solve the system of equations

x + 2 y + z = 0

x + y + 2 z = 7

2 x + y + z = 17

[4]
b.

Markscheme

( 1 2 1 1 1 2 2 1 4 ) 1 = ( 2 7 3 0 2 1 1 3 1 )         A2  N2

[2 marks]

a.

In matrix form A x  = B or x  = A1 B        M1

x = 2 , y = 3 , z = 4            A1A1A1   N0

[4 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 1—Number and algebra » AHL 1.14—Introduction to matrices
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Topic 1—Number and algebra

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