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Date May Example question Marks available 3 Reference code EXM.1.AHL.TZ0.10
Level Additional Higher Level Paper Paper 1 Time zone Time zone 0
Command term Find Question number 10 Adapted from N/A

Question

Let A(32k4) and B = (2213). Find, in terms of k,

2B.

[3]
a.

det (2B).

[3]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

 

2(642k8)          (A1)

2− B = (422k15)        A2   N3

[3 marks]

a.

Evidence of using the definition of determinant                    (M1)

Correct substitution                (A1)

eg 4(5) − 2(2k − 1), 20 − 2(2k 1), 20 − 4k + 2

det (2− B) = 22 − 4k               A1  N3

[3 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 1—Number and algebra » AHL 1.14—Introduction to matrices
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Topic 1—Number and algebra

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