Date | May 2018 | Marks available | 5 | Reference code | 18M.2.AHL.TZ1.H_11 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 1 |
Command term | Find | Question number | H_11 | Adapted from | N/A |
Question
Two submarines A and B have their routes planned so that their positions at time t hours, 0 ≤ t < 20 , would be defined by the position vectors rA and rB relative to a fixed point on the surface of the ocean (all lengths are in kilometres).
To avoid the collision submarine B adjusts its velocity so that its position vector is now given by
rB .
Show that the two submarines would collide at a point P and write down the coordinates of P.
Show that submarine B travels in the same direction as originally planned.
Find the value of t when submarine B passes through P.
Find an expression for the distance between the two submarines in terms of t.
Find the value of t when the two submarines are closest together.
Find the distance between the two submarines at this time.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
rA = rB (M1)
2 − t = − 0.5t ⇒ t = 4 A1
checking t = 4 satisfies 4 + t = 3.2 + 1.2t and − 1 − 0.15t = − 2 + 0.1t R1
P(−2, 8, −1.6) A1
Note: Do not award final A1 if answer given as column vector.
[4 marks]
A1
Note: Accept use of cross product equalling zero.
hence in the same direction AG
[1 mark]
M1
Note: The M1 can be awarded for any one of the resultant equations.
A1
[2 marks]
rA − rB = (M1)(A1)
(A1)
Note: Accept rA − rB.
distance M1A1
[5 marks]
minimum when (M1)
t = 3.83 A1
[2 marks]
0.511 (km) A1
[1 mark]