Date | May 2019 | Marks available | 5 | Reference code | 19M.1.AHL.TZ2.H_9 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 2 |
Command term | Find | Question number | H_9 | Adapted from | N/A |
Question
Consider the functions f and g defined on the domain 0<x<2π by f(x)=3cos2x and g(x)=4−11cosx.
The following diagram shows the graphs of y=f(x) and y=g(x)
Find the x-coordinates of the points of intersection of the two graphs.
Find the exact area of the shaded region, giving your answer in the form pπ+q√3, where p, q∈Q.
At the points A and B on the diagram, the gradients of the two graphs are equal.
Determine the y-coordinate of A on the graph of g.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
3cos2x=4−11cosx
attempt to form a quadratic in cosx M1
3(2cos2x−1)=4−11cosx A1
(6cos2x+11cosx−7=0)
valid attempt to solve their quadratic M1
(3cosx+7)(2cosx−1)=0
cosx=12 A1
x=π3,5π3 A1A1
Note: Ignore any “extra” solutions.
[6 marks]
consider (±) 5π3∫π3(4−11cosx−3cos2x)dx M1
=(±)[4x−11sinx−32sin2x]5π3π3 A1
Note: Ignore lack of or incorrect limits at this stage.
attempt to substitute their limits into their integral M1
=20π3−11sin5π3−32sin10π3−(4π3−11sinπ3−32sin2π3)
=16π3+11√32+3√34+11√32+3√34
=16π3+25√32 A1A1
[5 marks]
attempt to differentiate both functions and equate M1
−6sin2x=11sinx A1
attempt to solve for x M1
11sinx+12sinxcosx=0
sinx(11+12cosx)=0
cosx=−1112(orsinx=0) A1
⇒y=4−11(−1112) M1
y=16912(=14112) A1
[6 marks]