Date | May 2019 | Marks available | 2 | Reference code | 19M.2.AHL.TZ1.H_10 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 1 |
Command term | Write down | Question number | H_10 | Adapted from | N/A |
Question
The voltage in a circuit is given by the equation
, where is measured in seconds.
The current in this circuit is given by the equation
.
The power in this circuit is given by .
The average power in this circuit from to is given by the equation
, where .
Write down the maximum and minimum value of .
Write down two transformations that will transform the graph of onto the graph of .
Sketch the graph of for 0 ≤ ≤ 0.02 , showing clearly the coordinates of the first maximum and the first minimum.
Find the total time in the interval 0 ≤ ≤ 0.02 for which ≥ 3.
Find (0.007).
With reference to your graph of explain why > 0 for all > 0.
Given that can be written as where , , , > 0, use your graph to find the values of , , and .
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
3, −3 A1A1
[2 marks]
stretch parallel to the -axis (with -axis invariant), scale factor A1
translation of (shift to the left by 0.003) A1
Note: Can be done in either order.
[2 marks]
correct shape over correct domain with correct endpoints A1
first maximum at (0.0035, 4.76) A1
first minimum at (0.0085, −1.24) A1
[3 marks]
≥ 3 between = 0.0016762 and 0.0053238 and = 0.011676 and 0.015324 (M1)(A1)
Note: Award M1A1 for either interval.
= 0.00730 A1
[3 marks]
(M1)
= 2.87 A1
[2 marks]
in each cycle the area under the axis is smaller than area above the axis R1
the curve begins with the positive part of the cycle R1
[2 marks]
(M1)
A1
A1
A1
(M1)
A1
[6 marks]