Date | November 2014 | Marks available | 1 | Reference code | 14N.1.hl.TZ0.20 |
Level | HL | Paper | 1 | Time zone | TZ0 |
Command term | Question number | 20 | Adapted from | N/A |
Question
Consider the following reaction between nitrogen monoxide and oxygen.
\[{\text{2NO(g)}} + {{\text{O}}_{\text{2}}}{\text{(g)}} \to {\text{2N}}{{\text{O}}_{\text{2}}}{\text{(g)}}\]
The reaction occurs in two steps:
Step 1: \({\text{NO(g)}} + {\text{NO(g)}} \rightleftharpoons {{\text{N}}_{\text{2}}}{{\text{O}}_{\text{2}}}{\text{(g)}}\) fast
Step 2: \({{\text{N}}_{\text{2}}}{{\text{O}}_{\text{2}}}{\text{(g)}} + {{\text{O}}_{\text{2}}}{\text{(g)}} \to {\text{2N}}{{\text{O}}_{\text{2}}}{\text{(g)}}\) slow
What is the rate expression for this reaction?
A. Rate \( = k{{\text{[NO]}}^{\text{2}}}\)
B. Rate \( = k{\text{[NO][}}{{\text{O}}_{\text{2}}}{\text{]}}\)
C. Rate \( = k{{\text{[NO]}}^{\text{2}}}{\text{[}}{{\text{O}}_{\text{2}}}{\text{]}}\)
D. Rate \( = k{\text{[NO][}}{{\text{O}}_{\text{2}}}{{\text{]}}^{\text{2}}}\)
Markscheme
C
Examiners report
There were two comments. One suggested a “quantum change in difficulty” and the other commented that “students are not normally taught how to eliminate the intermediate from the rate expression for the slow step”. In the event, 82.71% of the candidates scored correctly, the sixth “easiest” question on the paper.