Date | November 2015 | Marks available | 3 | Reference code | 15N.2.sl.TZ0.2 |
Level | SL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 2 | Adapted from | N/A |
Question
The following table shows the probability distribution of a discrete random variable X.
Find the value of k.
[3]
a.
Find E(X).
[2]
b.
Markscheme
evidence of using ∑pi=1 (M1)
correct substitution A1
eg0.15+k+0.1+2k=1, 3k+0.25=1
k=0.25 A1 N2
[3 marks]
a.
correct substitution (A1)
eg0×0.15+1×0.25+2×0.1+3×0.5
E(X)=1.95 A1 N2
[2 marks]
Total [5 marks]
b.
Examiners report
[N/A]
a.
[N/A]
b.
Syllabus sections
Topic 5 - Statistics and probability » 5.7 » Concept of discrete random variables and their probability distributions.
Show 37 related questions