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Date November 2012 Marks available 3 Reference code 12N.1.sl.TZ0.1
Level SL only Paper 1 Time zone TZ0
Command term Find Question number 1 Adapted from N/A

Question

Let A=(0324) and  B=(4051).

Find AB .

[3]
a.

Given that X2A=B, find X.

[3]
b.

Markscheme

evidence of multiplying     (M1)

e.g. one correct element, (0×4)+(3×5)

AB=(153284)     A2     N3

Note: Award A1 for three correct elements.

[3 marks]

a.

finding 2A=(0648)     (A1)

adding 2A to both sides (may be seen first)     (M1)

e.g. X=B+2A

 X=(4619)     A1     N2

[3 marks]

b.

Examiners report

The large majority of candidates answered this question successfully. There were only a small number of candidates who seemed to have never worked with matrices before. Occasionally a candidate would incorrectly approach part (b) by finding an inverse of matrix A.

a.

The large majority of candidates answered this question successfully. There were only a small number of candidates who seemed to have never worked with matrices before. Occasionally a candidate would incorrectly approach part (b) by finding an inverse of matrix A.

b.

Syllabus sections

Topic 5 - Statistics and probability » 5.7 » Concept of discrete random variables and their probability distributions.
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