Date | November 2012 | Marks available | 3 | Reference code | 12N.1.sl.TZ0.1 |
Level | SL only | Paper | 1 | Time zone | TZ0 |
Command term | Find | Question number | 1 | Adapted from | N/A |
Question
Let A=(03−24) and B=(−4051).
Find AB .
Given that X−2A=B, find X.
Markscheme
evidence of multiplying (M1)
e.g. one correct element, (0×−4)+(3×5)
AB=(153284) A2 N3
Note: Award A1 for three correct elements.
[3 marks]
finding 2A=(06−48) (A1)
adding 2A to both sides (may be seen first) (M1)
e.g. X=B+2A
X=(−4619) A1 N2
[3 marks]
Examiners report
The large majority of candidates answered this question successfully. There were only a small number of candidates who seemed to have never worked with matrices before. Occasionally a candidate would incorrectly approach part (b) by finding an inverse of matrix A.
The large majority of candidates answered this question successfully. There were only a small number of candidates who seemed to have never worked with matrices before. Occasionally a candidate would incorrectly approach part (b) by finding an inverse of matrix A.