Date | November 2011 | Marks available | 6 | Reference code | 11N.1.sl.TZ0.5 |
Level | SL only | Paper | 1 | Time zone | TZ0 |
Command term | Find | Question number | 5 | Adapted from | N/A |
Question
The random variable X has the following probability distribution.
Given that \({\rm{E}}(X) = 1.7\) , find q .
Markscheme
correct substitution into \({\rm{E}}(X) = \sum {px} \) (seen anywhere) A1
e.g. \(1s + 2 \times 0.3 + 3q = 1.7\) , \(s + 3q = 1.1\)
recognizing \(\sum {p = 1} \) (seen anywhere) (M1)
correct substitution into \(\sum {p = 1} \) A1
e.g. \(s + 0.3 + q = 1\)
attempt to solve simultaneous equations (M1)
correct working (A1)
e.g. \(0.3 + 2q = 0.7\) , \(2s = 1\)
\(q = 0.2\) A1 N4
[6 marks]
Examiners report
Candidates generally earned either full marks or only one mark on this question. The most common error was where candidates only wrote the equation for \({\rm{E}}(X) = 1.7\) , and tried to rearrange that equation to solve for q. The candidates who also knew that the sum of the probabilities must be equal to 1 were very successful in solving the resulting system of equations.