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Date November 2011 Marks available 6 Reference code 11N.1.sl.TZ0.5
Level SL only Paper 1 Time zone TZ0
Command term Find Question number 5 Adapted from N/A

Question

The random variable X has the following probability distribution.

Given that E(X)=1.7 , find q .

Markscheme

correct substitution into E(X)=px (seen anywhere)     A1

e.g. 1s+2×0.3+3q=1.7 , s+3q=1.1

recognizing p=1 (seen anywhere)     (M1)

correct substitution into p=1     A1

e.g. s+0.3+q=1

attempt to solve simultaneous equations     (M1)

correct working     (A1)

e.g. 0.3+2q=0.7 , 2s=1

q=0.2     A1     N4

[6 marks]

Examiners report

Candidates generally earned either full marks or only one mark on this question. The most common error was where candidates only wrote the equation for E(X)=1.7 , and tried to rearrange that equation to solve for q. The candidates who also knew that the sum of the probabilities must be equal to 1 were very successful in solving the resulting system of equations.

Syllabus sections

Topic 5 - Statistics and probability » 5.7 » Concept of discrete random variables and their probability distributions.
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