Date | May 2010 | Marks available | 4 | Reference code | 10M.2.sl.TZ2.2 |
Level | SL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 2 | Adapted from | N/A |
Question
An arithmetic sequence, u1, u2, u3…, has d=11 and u27=263 .
Find u1.
(i) Given that un=516 , find the value of n .
(ii) For this value of n , find Sn .
Markscheme
evidence of equation for u27 M1
e.g. 263=u1+26×11 , u27=u1+(n−1)×11 , 263−(11×26)
u1=−23 A1 N1
[2 marks]
(i) correct equation A1
e.g. 516=−23+(n−1)×11 , 539=(n−1)×11
n=50 A1 N1
(ii) correct substitution into sum formula A1
e.g. S50=50(−23+516)2 , S50=50(2×(−23)+49×11)2
S50=12325 (accept 12300) A1 N1
[4 marks]
Examiners report
This problem was done well by the vast majority of candidates. Most students set out their working very neatly and logically and gained full marks.
This problem was done well by the vast majority of candidates. Most students set out their working very neatly and logically and gained full marks.