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Date May 2010 Marks available 4 Reference code 10M.2.sl.TZ2.2
Level SL only Paper 2 Time zone TZ2
Command term Find Question number 2 Adapted from N/A

Question

An arithmetic sequence, u1u2u3, has d=11 and u27=263 .

Find u1.

[2]
a.

(i)     Given that un=516 , find the value of n .

(ii)    For this value of n , find Sn .

[4]
b(i) and (ii).

Markscheme

evidence of equation for u27     M1

e.g. 263=u1+26×11 , u27=u1+(n1)×11 , 263(11×26)

u1=23     A1     N1

[2 marks]

a.

(i) correct equation     A1

e.g. 516=23+(n1)×11 , 539=(n1)×11

n=50     A1     N1

(ii) correct substitution into sum formula     A1

e.g. S50=50(23+516)2 , S50=50(2×(23)+49×11)2

S50=12325 (accept 12300)     A1     N1

[4 marks]

b(i) and (ii).

Examiners report

This problem was done well by the vast majority of candidates. Most students set out their working very neatly and logically and gained full marks.

a.

This problem was done well by the vast majority of candidates. Most students set out their working very neatly and logically and gained full marks.

b(i) and (ii).

Syllabus sections

Topic 1 - Algebra » 1.1 » Arithmetic sequences and series; sum of finite arithmetic series; geometric sequences and series; sum of finite and infinite geometric series.
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