Date | May 2008 | Marks available | 3 | Reference code | 08M.1.sl.TZ1.3 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 3 | Adapted from | N/A |
Question
Consider the arithmetic sequence 2, 5, 8, 11,… .
Find u101 .
Consider the arithmetic sequence 2, 5, 8, 11,… .
Find the value of n so that un=152 .
Markscheme
d=3 (A1)
evidence of substitution into un=a+(n−1)d (M1)
e.g. u101=2+100×3
u101=302 A1 N3
[3 marks]
correct approach (M1)
e.g. 152=2+(n−1)×3
correct simplification (A1)
e.g. 150=(n−1)×3 , 50=n−1 , 152=−1+3n
n=51 A1 N2
[3 marks]
Examiners report
Candidates probably had the most success with this question with many good solutions which were written with the working clearly shown. Many used the alternate approach of un=3n−1 .
Candidates probably had the most success with this question with many good solutions which were written with the working clearly shown. Many used the alternate approach of un=3n−1 .