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Date May 2022 Marks available 1 Reference code 22M.1.SL.TZ1.2
Level Standard Level Paper Paper 1 (without calculator) Time zone Time zone 1
Command term Write down Question number 2 Adapted from N/A

Question

The expression 3x-5x can be written as 3-5xp. Write down the value of p.

[1]
a.

Hence, find the value of 91(3x-5x)dx.

[4]
b.

Markscheme

3x-5x=3-5x-12       A1

p=-12

 

[1 mark]

a.

3x-5xdx=3x-10x12(+c)             A1A1

substituting limits into their integrated function and subtracting             (M1)

3(9)-10(9)12-(3(1)-10(1)12)  OR  27-10×3-(3-10)

=4             A1

 

[4 marks]

b.

Examiners report

Many candidates could give the value of p correctly. However, many did struggle with the integration, including substituting limits into the integrand, without integrating at all. An incorrect value of p often resulted in arithmetic of greater complexity.

a.
[N/A]
b.

Syllabus sections

Topic 1—Number and algebra » SL 1.7—Laws of exponents and logs
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Topic 1—Number and algebra

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