Date | November Example questions | Marks available | 5 | Reference code | EXN.1.SL.TZ0.2 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Solve | Question number | 2 | Adapted from | N/A |
Question
Solve the equation 2 ln x= ln 9+4. Give your answer in the form x=peq where p, q∈ℤ+.
Markscheme
* This sample question was produced by experienced DP mathematics senior examiners to aid teachers in preparing for external assessment in the new MAA course. There may be minor differences in formatting compared to formal exam papers.
METHOD 1
2 ln x- ln 9=4
uses m ln x= ln xm (M1)
ln x2- ln 9=4
uses ln a- ln b=ln ab (M1)
ln x29=4
x29=e4 A1
x2=9e4⇒x=√9e4 (x>0) A1
x=3e2 (p=3, q=2) A1
METHOD 2
expresses 4 as 4 ln e and uses ln xm=m ln x (M1)
2 ln x=2 ln 3+4 ln e (ln x=ln 3+2 ln e) A1
uses 2 ln e=ln e2 and ln a+ln b=ln ab (M1)
ln x=ln (3e2) A1
x=3e2 (p=3, q=2) A1
METHOD 3
expresses 4 as 4 ln e and uses m ln x=ln xm (M1)
ln x2=ln 32+ln e4 A1
uses ln a+ln b=ln ab (M1)
ln x2=ln (32 e4)
x2=32 e4⇒x=√32 e4 (x>0) A1
so x=3e2 (x>0) (p=3, q=2) A1
[5 marks]