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Date November 2021 Marks available 5 Reference code 21N.1.AHL.TZ0.3
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 0
Command term Solve Question number 3 Adapted from N/A

Question

Solve the equation log3x=12log23+log34x3, where x>0.

Markscheme

attempt to use change the base                (M1)

log3x=log322+log34x3

attempt to use the power rule                (M1)

log3x=log32+log34x3

attempt to use product or quotient rule for logs, lna+lnb=lnab                (M1)

log3x=log342x3


Note:
The M marks are for attempting to use the relevant log rule and may be applied in any order and at any time during the attempt seen.


x=42x3

x=32x6

x5=132                (A1)

x=12                A1

 

[5 marks]

Examiners report

[N/A]

Syllabus sections

Topic 1—Number and algebra » SL 1.7—Laws of exponents and logs
Show 49 related questions
Topic 2—Functions » SL 2.9—Exponential and logarithmic functions
Topic 1—Number and algebra
Topic 2—Functions

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