Date | November 2017 | Marks available | 5 | Reference code | 17N.1.AHL.TZ0.H_1 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Solve | Question number | H_1 | Adapted from | N/A |
Question
Solve the equation log2(x+3)+log2(x−3)=4.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
log2(x+3)+log2(x−3)=4
log2(x2−9)=4 (M1)
x2−9=24 (=16) M1A1
x2=25
x=±5 (A1)
x=5 A1
[5 marks]
Examiners report
[N/A]