Date | May 2021 | Marks available | 4 | Reference code | 21M.2.SL.TZ1.9 |
Level | Standard Level | Paper | Paper 2 | Time zone | Time zone 1 |
Command term | Find | Question number | 9 | Adapted from | N/A |
Question
Consider the function defined by for .
The graph of and the line intersect at point .
The line has a gradient of and is a tangent to the graph of at the point .
The shaded region is enclosed by the graph of and the lines and .
Find the -coordinate of .
Find the exact coordinates of .
Show that the equation of is .
Find the -coordinate of the point where intersects the line .
Hence, find the area of .
The line is tangent to the graphs of both and the inverse function .
Find the shaded area enclosed by the graphs of and and the line .
Markscheme
Attempt to find the point of intersection of the graph of and the line (M1)
A1
[2 marks]
A1
attempt to set the gradient of equal to (M1)
has coordinates (accept () A1A1
Note: Award A1 for each value, even if the answer is not given as a coordinate pair.
Do not accept or as a final value for . Do not accept or as a final value for .
[4 marks]
attempt to substitute coordinates of (in any order) into an appropriate equation (M1)
OR A1
equation of is AG
[2 marks]
A1
[1 mark]
appropriate method to find the sum of two areas using integrals of the difference of two functions (M1)
Note: Allow absence of incorrect limits.
(A1)(A1)
Note: Award A1 for one correct integral expression including correct limits and integrand.
Award A1 for a second correct integral expression including correct limits and integrand.
A1
[4 marks]
by symmetry (M1)
A1
Note: Accept any answer that rounds to (but do not accept ).
[2 marks]