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Date November 2018 Marks available 2 Reference code 18N.1.SL.TZ0.T_11
Level Standard Level Paper Paper 1 (with calculator from previous syllabus) Time zone Time zone 0
Command term Find Question number T_11 Adapted from N/A

Question

Consider the curve y = 5x3 − 3x.

The curve has a tangent at the point P(−1, −2).

Find the equation of this tangent. Give your answer in the form y = mx + c.

Markscheme

(y − (−2)) = 12 (x − (−1))     (M1)

OR

−2 = 12(−1) + c     (M1)

Note: Award  (M1) for point and their gradient substituted into the equation of a line.

 

y = 12x + 10     (A1)(ft) (C2)

Note: Follow through from part (b).

 

[2 marks]

Examiners report

[N/A]

Syllabus sections

Topic 5 —Calculus » SL 5.4—Tangents and normal
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Topic 5 —Calculus

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