Date | November 2020 | Marks available | 1 | Reference code | 20N.2.SL.TZ0.S_7 |
Level | Standard Level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Show that | Question number | S_7 | Adapted from | N/A |
Question
The following diagram shows a circle with centre OO and radius 1 cm1cm. Points AA and BB lie on the circumference of the circle and AˆOB=2θAˆOB=2θ, where 0<θ<π20<θ<π2.
The tangents to the circle at AA and BB intersect at point CC.
Show that AC=tan θAC=tanθ.
Find the value of θθ when the area of the shaded region is equal to the area of sector OADBOADB.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
correct working for ACAC (seen anywhere) A1
eg tan θ=ACOA, tan θ=AC1tanθ=ACOA, tanθ=AC1
AC=tan θAC=tanθ AG N0
[1 mark]
METHOD 1 (working with half the areas)
area of triangle OACOAC or triangle OBCOBC (A1)
eg 12×1×tan θ12×1×tanθ
correct sector area (A1)
eg 12×θ×(12) , 12θ12×θ×(12) , 12θ
correct approach using their areas to find the shaded area (seen anywhere) (A1)
eg Atheir triangle-Atheir sector , 12θ-12tan θAtheir triangle−Atheir sector , 12θ−12tanθ
correct equation A1
eg 12tan θ-12θ=12θ , tan θ=2θ12tanθ−12θ=12θ , tanθ=2θ
1.165561.16556
1.171.17 A2 N4
METHOD 2 (working with entire kite and entire sector)
area of kite OACBOACB (A1)
eg 2×12×1×tan θ , 12×1cos θ×2 sin θ2×12×1×tanθ , 12×1cosθ×2sinθ
correct sector area (A1)
eg 12×2θ×(12) , θ12×2θ×(12) , θ
correct approach using their areas to find the shaded area (seen anywhere) (A1)
eg Akite OACB-Asector OADB , θ-tan θAkite OACB−Asector OADB , θ−tanθ
correct equation A1
eg tan θ-θ=θ , tan θ=2θtanθ−θ=θ , tanθ=2θ
1.165561.16556
1.171.17 A2 N4
[6 marks]