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Date November 2019 Marks available 2 Reference code 19N.2.AHL.TZ0.H_4
Level Additional Higher Level Paper Paper 2 Time zone Time zone 0
Command term Calculate Question number H_4 Adapted from N/A

Question

The following shape consists of three arcs of a circle, each with centre at the opposite vertex of an equilateral triangle as shown in the diagram.

For this shape, calculate

the perimeter.

[2]
a.

the area.

[5]
b.

Markscheme

each arc has length  r θ = 6 × π 3 = 2 π ( = 6.283 )        (M1)

perimeter is therefore  6 π ( = 18.8 ) (cm)        A1

[2 marks]

a.

area of sector, s , is  1 2 r 2 θ = 18 × π 3 = 6 π ( = 18.84 )        (A1)

area of triangle, t , is  1 2 × 6 × 3 3 = 9 3 ( = 15.58 )        (M1)(A1)

Note: area of segment, k , is 3.261… implies area of triangle

finding  3 s 2 t or  3 k + t or similar

area  = 3 s 2 t = 18 π 18 3 ( = 25.4 )  (cm2)       (M1)A1

[5 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 3— Geometry and trigonometry » SL 3.4—Circle: radians, arcs, sectors
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Topic 3— Geometry and trigonometry

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