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Date November 2019 Marks available 2 Reference code 19N.2.SL.TZ0.S_4
Level Standard Level Paper Paper 2 Time zone Time zone 0
Command term Find Question number S_4 Adapted from N/A

Question

The following diagram shows a right-angled triangle, ABC, with AC=10cmAB=6cm and BC=8cm.

The points D and F lie on [AC].
[BD] is perpendicular to [AC].
BEF is the arc of a circle, centred at A.
The region R is bounded by [BD], [DF] and arc BEF.

Find BˆAC.

[2]
a.

Find the area of R.

[5]
b.

Markscheme

correct working        (A1)

eg       sinα=810,  cosθ=610,  cosBˆAC=62+102822×6×10

0.927295

BˆAC=0.927  (=53.1)      (A1)  N2

[2 marks]

a.

Note: There may be slight differences in the final answer, depending on the approach the candidate uses in part (b). Accept a final answer that is consistent with their working.

correct area of sector ABF (seen anywhere)        (A1)

eg       12×62×0.927,  53.1301360×π×62,  16.6913

correct expression (or value) for either [AD] or [BD] (seen anywhere)        (A1)

eg       AD=6cos(BˆAC)(=3.6)

           BD=6sin(53.1)(=4.8)

correct area of triangle ABD (seen anywhere)        (A1)

eg       12×6cosBˆAD×6sinBˆAD,  9sin(2BˆAC)8.64 (exact)

appropriate approach (seen anywhere)        (M1)

eg       Atriangle ABDAsector,  their sector − their triangle ABD

8.05131

area of shaded region =8.05 (cm2)       A1  N2

[5 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 3— Geometry and trigonometry » SL 3.4—Circle: radians, arcs, sectors
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Topic 3— Geometry and trigonometry

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