Date | May 2018 | Marks available | 2 | Reference code | 18M.2.hl.TZ2.1 |
Level | HL only | Paper | 2 | Time zone | TZ2 |
Command term | Express | Question number | 1 | Adapted from | N/A |
Question
Consider the complex number z=2+7i6+2iz=2+7i6+2i.
Express zz in the form a+iba+ib, where a,b∈Q.
Find the exact value of the modulus of z.
Find the argument of z, giving your answer to 4 decimal places.
Markscheme
z=(2+7i)(6+2i)×(6−2i)(6−2i) (M1)
=26+38i40=(13+19i20=0.65+0.95i) A1
[2 marks]
attempt to use |z|=√a2+b2 (M1)
|z|=√5340(=√53020) or equivalent A1
Note: A1 is only awarded for the correct exact value.
[2 marks]
EITHER
arg z = arg(2 + 7i) − arg(6 + 2i) (M1)
OR
arg z = arctan(1913) (M1)
THEN
arg z = 0.9707 (radians) (= 55.6197 degrees) A1
Note: Only award the last A1 if 4 decimal places are given.
[2 marks]