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Date May 2013 Marks available 7 Reference code 13M.2.sl.TZ1.7
Level SL only Paper 2 Time zone TZ1
Command term Find Question number 7 Adapted from N/A

Question

A random variable \(X\) is normally distributed with \(\mu  = 150\) and \(\sigma  = 10\) .

Find the interquartile range of \(X\) .

Markscheme

recognizing one quartile probability (may be seen in a sketch)     (M1)

eg   \({\rm{P}}(X < {Q_3}) = 0.75\) , \(0.25\)

finding standardized value for either quartile     (A1)

eg   \(z = 0.67448 \ldots \) , \(z = - 0.67448 \ldots \)

attempt to set up equation (must be with \(z\)-values)     (M1)

eg   \(0.67 = \frac{{{Q_3} - 150}}{{10}}\) , \( - 0.67448 = \frac{{x - 150}}{{10}}\)

one correct quartile

eg   \({Q_3} = 156.74 \ldots \) , \({Q_1} = 143.25 \ldots \)

correct working     (A1)

eg   other correct quartile, \({Q_3} - \mu  = 6.744 \ldots \)

valid approach for IQR (seen anywhere)     (A1)

eg   \({Q_3} - {Q_1}\) , \(2({Q_3} - \mu )\)

IQR \( = 13.5\)     A1     N4

[7 marks]

Examiners report

This was an accessible problem that created difficulties for candidates. Although they recognized and often wrote down a formula for IQR, most did not understand the conceptual nature of the first and third quartiles. Those who did could solve the problem effectively using their GDC in relatively few steps. Candidates that were able to start this question often drew the normal curve and gave quartile values at \(140\) and \(160\). This generally led to a solution which while wrong, was also clearly inadequate for the indicated 7 marks.

Syllabus sections

Topic 5 - Statistics and probability » 5.9 » Normal distributions and curves.
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