Date | November 2008 | Marks available | 3 | Reference code | 08N.2.sl.TZ0.7 |
Level | SL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 7 | Adapted from | N/A |
Question
The scores of a test given to students are normally distributed with a mean of 21. 80% of the students have scores less than 23.7.
Find the standard deviation of the scores.
A student is chosen at random. This student has the same probability of having a score less than 25.4 as having a score greater than b.
(i) Find the probability the student has a score less than 25.4.
(ii) Find the value of b.
Markscheme
evidence of approach (M1)
e.g. finding 0.84…, using 23.7−21σ
correct working (A1)
e.g. 0.84…=23.7−21σ , graph A1
σ=3.21
[3 marks]
(i) evidence of attempting to find P(X<25.4) (M1)
e.g. using z=1.37
P(X<25.4)=0.915 A1 N2
(ii) evidence of recognizing symmetry (M1)
e.g. b=21−4.4 , using z=−1.37 A1 N2
[4 marks]
Examiners report
Candidates who clearly understood the nature of normal probability answered this question cleanly. A common misunderstanding was to use the value of 0.8 as a z-score when finding the standard deviation.
Many correctly used their GDC to find the probability in part (b). Fewer used some aspect of the symmetry of the curve to find a value for b.