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Date November 2013 Marks available 5 Reference code 13N.2.sl.TZ0.6
Level SL only Paper 2 Time zone TZ0
Command term Find Question number 6 Adapted from N/A

Question

The time taken for a student to complete a task is normally distributed with a mean of 20 minutes and a standard deviation of 1.25 minutes.

A student is selected at random. Find the probability that the student completes the task in less than 21.8 minutes.

[2]
a.

The probability that a student takes between k and 21.8 minutes is 0.3. Find the value of k.

[5]
b.

Markscheme

Note: There may be slight differences in answers, depending on whether candidates use tables or GDCs, or their 3 sf answers in subsequent parts. Do not penalise answers that are consistent with their working and check carefully for FT.

 

attempt to standardize     (M1)

eg     z=21.8201.25, 1.44

P(T<21.8)=0.925     A1     N2

[2 marks]

a.

Note: There may be slight differences in answers, depending on whether candidates use tables or GDCs, or their 3 sf answers in subsequent parts. Do not penalise answers that are consistent with their working and check carefully for FT.

 

attempt to subtract probabilities     (M1)

eg     P(T<21.8)P(T<k)=0.3, 0.9250.3

P(T<k)=0.625     A1

EITHER

finding the z-value for 0.625     (A1)

eg     z=0.3186 (from tables), z=0.3188

attempt to set up equation using their z-value     (M1)

eg     0.3186=k201.25, 0.524×1.25=k20

k=20.4     A1     N3

OR

k=20.4     A3     N3

[5 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 5 - Statistics and probability » 5.9 » Normal distributions and curves.
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