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Date May 2011 Marks available 4 Reference code 11M.1.sl.TZ2.5
Level SL only Paper 1 Time zone TZ2
Command term Express Question number 5 Adapted from N/A

Question

Let f(x)=3lnx and g(x)=ln5x3 .

Express g(x) in the form f(x)+lna , where aZ+ .

[4]
a.

The graph of g is a transformation of the graph of f . Give a full geometric description of this transformation.

[3]
b.

Markscheme

attempt to apply rules of logarithms     (M1)

e.g. lnab=blna , lnab=lna+lnb

correct application of lnab=blna (seen anywhere)     A1

e.g. 3lnx=lnx3

correct application of lnab=lna+lnb (seen anywhere)     A1

e.g. ln5x3=ln5+lnx3

so ln5x3=ln5+3lnx

g(x)=f(x)+ln5 (accept g(x)=3lnx+ln5 )     A1     N1

[4 marks]

a.

transformation with correct name, direction, and value     A3

e.g. translation by (0ln5) , shift up by ln5 , vertical translation of ln5

[3 marks]

b.

Examiners report

This question was very poorly done by the majority of candidates. While candidates seemed to have a vague idea of how to apply the rules of logarithms in part (a), very few did so successfully. The most common error in part (a) was to begin incorrectly with ln5x3=3ln5x . This error was often followed by other errors.

a.

In part (b), very few candidates were able to describe the transformation as a vertical translation (or shift). Many candidates attempted to describe numerous incorrect transformations, and some left part (b) entirely blank.

b.

Syllabus sections

Topic 2 - Functions and equations » 2.3 » Transformations of graphs.
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