Date | May 2018 | Marks available | 5 | Reference code | 18M.2.AHL.TZ1.H_9 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 1 |
Command term | Find | Question number | H_9 | Adapted from | N/A |
Question
The following graph shows the two parts of the curve defined by the equation , and the normal to the curve at the point P(2 , 1).
Show that there are exactly two points on the curve where the gradient is zero.
Find the equation of the normal to the curve at the point P.
The normal at P cuts the curve again at the point Q. Find the -coordinate of Q.
The shaded region is rotated by 2 about the -axis. Find the volume of the solid formed.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
differentiating implicitly: M1
A1A1
Note: Award A1 for each side.
if then either or M1A1
two solutions for R1
not possible (as 0 ≠ 5) R1
hence exactly two points AG
Note: For a solution that only refers to the graph giving two solutions at and no solutions for award R1 only.
[7 marks]
at (2, 1) M1
(A1)
gradient of normal is 2 M1
1 = 4 + c (M1)
equation of normal is A1
[5 marks]
substituting (M1)
or (A1)
A1
[3 marks]
recognition of two volumes (M1)
volume M1A1A1
Note: Award M1 for attempt to use , A1 for limits, A1 for Condone omission of at this stage.
volume 2
EITHER
(M1)(A1)
OR
(M1)(A1)
THEN
total volume = 19.9 A1
[7 marks]