Date | November 2018 | Marks available | 4 | Reference code | 18N.2.AHL.TZ0.H_9 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Find | Question number | H_9 | Adapted from | N/A |
Question
The function is defined by , 0 < < 3.
Draw a set of axes showing and values between −3 and 3. On these axes
Find .
Hence, or otherwise, find the coordinates of the point of inflexion on the graph of .
sketch the graph of , showing clearly any axis intercepts and giving the equations of any asymptotes.
sketch the graph of , showing clearly any axis intercepts and giving the equations of any asymptotes.
Hence, or otherwise, solve the inequality .
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
METHOD 1
(M1)A1A1A1
Note: Award M1 for attempt at quotient rule, A1A1 for numerator and A1 for denominator.
METHOD 2
(A1)
(M1)A1A1
Note: Award M1 for attempt at product rule, A1 for first term, A1 for second term.
[4 marks]
finding turning point of or finding root of (M1)
A1
(M1)A1
(0.899, −0.375)
Note: Do not accept . Accept y-coordinates rounding to −0.37 or −0.375 but not −0.38.
[4 marks]
smooth curve over the correct domain which does not cross the y-axis
and is concave down for > 1 A1
-intercept at 0.607 A1
equations of asymptotes given as = 0 and = 3 (the latter must be drawn) A1A1
[4 marks]
attempt to reflect graph of in = (M1)
smooth curve over the correct domain which does not cross the -axis and is concave down for > 1 A1
-intercept at 0.607 A1
equations of asymptotes given as = 0 and = 3 (the latter must be drawn) A1
Note: For FT from (i) to (ii) award max M1A0A1A0.
[4 marks]
solve or to get = 0.372 (M1)A1
0 < < 0.372 A1
Note: Do not award FT marks.
[3 marks]