Date | November 2021 | Marks available | 3 | Reference code | 21N.2.SL.TZ0.7 |
Level | Standard Level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Find | Question number | 7 | Adapted from | N/A |
Question
Points A and P lie on opposite banks of a river, such that AP is the shortest distance across the river. Point B represents the centre of a city which is located on the riverbank. PB=215 km, AP=65 km and AˆPB=90°.
The following diagram shows this information.
A boat travels at an average speed of 42 km h-1. A bus travels along the straight road between P and B at an average speed of 84 km h-1.
Find the travel time, in hours, from A to B given that
There is a point D, which lies on the road from P to B, such that BD=x km. The boat travels from A to D, and the bus travels from D to B.
An excursion involves renting the boat and the bus. The cost to rent the boat is $ 200 per hour, and the cost to rent the bus is $ 150 per hour.
the boat is taken from A to P, and the bus from P to B.
the boat travels directly to B.
Find an expression, in terms of x for the travel time T, from A to B, passing through D.
Find the value of x so that T is a minimum.
Write down the minimum value of T.
Find the new value of x so that the total cost C to travel from A to B via D is a minimum.
Write down the minimum total cost for this journey.
Markscheme
AP42 OR 21584 OR 6542+21584 (M1)
time =4.10714… (hours)
time =4.11 (hours) A1
[2 marks]
AB=√2152+652(=224.610…) (A1)
time =5.34787… (hours)
time =5.35 (hours) A1
[2 marks]
AD=√(215-x)2+652 (A1)
t=√(215-x)2+65242 (A1)
T=√(215-x)2+65242+x84(=√x2-430x+5045042+x84) A1
[3 marks]
valid approach to find the minimum for T (may be seen in (iii)) (M1)
graph of T OR T'=0 OR graph of T'
x=177.472… km
x=177 km A1
[2 marks]
T=3.89980…
T=3.90 (hours) A1
Note: Only allow FT in (b)(ii) and (iii) for 0<x<215 and a function T that has a minimum in that interval.
[1 mark]
C=200·√(215-x)2+65242+150·x84 (A1)
valid approach to find the minimum for C(x) (may be seen in (ii)) (M1)
graph of C OR C'=0 OR graph of C'
x=188.706… km
x=189 km A1
Note: Only allow FT from (b) if the function T has a minimum in 0<x<215.
[3 marks]
C=670.864
C=$671 A1
Note: Only allow FT from (c)(i) if the function C has a minimum in 0<x<215.
[1 mark]